Character Creation.

[Spearmint]

Welcome to the game Grokkngrognard. Maybe not a paladin from the get-go, but you can certainly have Templar ambitions (if 'the dark side' doesn't call you first ...).

[subaltari]

Stat Rolls: [4d6c1]=10 [4d6c1]=10 [4d6c1]=14 [4d6c1]=17 [4d6c1]=7 [4d6c1]=11

So close! Paladin-in' ain't easy.

Welcome aboard grokkngrognard!

[Rex]

Welcome aboard grokkngrognard!

[kruk]

Hello all

Berrgen Chiselrock at your service

Stat rolls: [4d6c1]=9,[4d6c1]=9,[4d6c1]=18,[4d6c1]=11,[4d6c1]=9,[4d6c1]=8.

Interesting rolls from the dice gods

Starting Gold[3d6]=12

[Stirling]

Must be summer season with all the new players joining!

Welcome kruk

[subaltari]

Stat rolls: [4d6c1]=9,[4d6c1]=9,[4d6c1]=18,[4d6c1]=11,[4d6c1]=9,[4d6c1]=8.

Put that 18 into CHA for sure

Welcome aboard, kruk !

[Spearmint]

Welcome kruk to the game.

There is no requirement to post the attribute scores as they can be viewed in the dice roller archive, but celebrating an 18 is good. I think only three of fifty plus characters have actually rolled an unmodified 18.

Sunday trivia:

To calculate the probability of getting three sixes in four rolls of a fair six-sided die, we can use the binomial probability formula. The probability of getting a six on a single roll of the die is 1/6, and the probability of not getting a six is 5/6.

Using the binomial probability formula, the probability of getting exactly three sixes in four rolls is:

P(X = 3) = (4 choose 3) * (1/6)^3 * (5/6)^(4-3)

Where (4 choose 3) = 4! / (3!(4-3)!) = 4, and ^ denotes exponentiation.

So, the probability of getting three sixes in four rolls of a fair six-sided die is:

P(X = 3) = 4 * (1/6)^3 * (5/6)^1 = 80 / 1296 ≈ 0.0617 or approximately 6.17%.

[Rex]

Welcome Aboard kruk!

[BaltoBruiser]

Welcome kruk to the game.

There is no requirement to post the attribute scores as they can be viewed in the dice roller archive, but celebrating an 18 is good. I think only three of fifty plus characters have actually rolled an unmodified 18.

Sunday trivia:

To calculate the probability of getting three sixes in four rolls of a fair six-sided die, we can use the binomial probability formula. The probability of getting a six on a single roll of the die is 1/6, and the probability of not getting a six is 5/6.

Using the binomial probability formula, the probability of getting exactly three sixes in four rolls is:

P(X = 3) = (4 choose 3) * (1/6)^3 * (5/6)^(4-3)

Where (4 choose 3) = 4! / (3!(4-3)!) = 4, and ^ denotes exponentiation.

So, the probability of getting three sixes in four rolls of a fair six-sided die is:

P(X = 3) = 4 * (1/6)^3 * (5/6)^1 = 80 / 1296 ≈ 0.0617 or approximately 6.17%.

That is alot of maths...but I appreciate it.

Welcome Kruk

[kwll]

Welcome to all newcomers!

[Jernau35]

Hello and welcome, Kruk!